The estimate of the electric demand：

 

At ordinary times：

 

 

Emergency：

 

 

115KwH/d ; 770 people's power consumption

 

 

 83.2KwH/d; 500 people's power consumption

 

 

↓

 

 

The estimate of the Mould-Group area：
*The intensity of sunshine: 1Kw/m2 ：1Kw/m2

*the sunshine time：3.84H/d

*the efficiency of the Mould-Group：12%

 

 

The electric demands ÷(the intensity of sunshine × the sunshine time × the efficiency of the Mould-Group × the omprehensive coefficient)

 

 

The comprehensive coefficient: temperature changes, defilement, line loss , inverter efficiency + battery charge-discharge and compensation

 

 

At ordinary times： 0.65~0.8

 

 

Emergency： 0.57

 

 

115KwH/d÷1Kw/m2÷3.84H/d÷12﹪÷0.75＝332 m2

 

 

83.2KwH/d÷1Kw/m2÷3.84H/d÷12﹪÷0.57＝317 m2

 

 

↓
Take Max 332 m2.  Only supply for emergent using, take 317 m2

 

 

Calculate the capacity of the installation：

 

 

the capacity of the installation of the solar power energy system ＝ the square measure of installation × the intensity of sunshine  × the efficiency of the Mould-Group

 

 

332m2×1Kw/m2×12﹪＝39.8Kw≒40Kw

 

 

↓

 

 

The generation of calculation：

 

 

The generation of the solar power energy system ＝ the capacity of the installation × the sunshine time × the comprehensive coefficient

 

 

At ordinary times：
0Kw×3.84H/d×0.75＝115.2wH/d

 

 

Emergency：
40kw×3.84H/d×0.57＝87.5KwH/d

 

 

↓

 

 

Whether it comforms the calculation of the electric demands or not?

 

 

↓ Yes

 

 

Carry on the design of the array of template and the capacity of battery

 

 

The design of the array of template:

*The power of the template：120W

*The outputs voltage of the templat：6.9V

*The inputs voltage of the inverter：300V

 

The amount of series-wound array＝ the inputs voltage of the inverter ÷ the outputs voltage of the templat.

 

300V ÷ 16.9V ＝ 17.75 pieces (take integer 17 or 18)

 

 

The power of the single series：

 

 

17 pieces ×120W＝2040W

 

 

18 pieces ×120W＝2160W

 

 

The parallel amount of the array ＝ the capacity of the installation ÷ the power of the single series

 

 

40Kw ÷ 17 pieces / series ÷ 120W ＝ 19.6 arrays  ≒  20 arrays

 

 

40Kw ÷ 18 pieces/ series ÷ 120W ＝ 18.5arrays   ≒   19arrays

 

 

↓

 

 

Choose the best array：

 

 

The best array: More economic capacity of installation

 

 

120W × 17 pieces/series × 20 arrays = 40800W = 340 pieces (the best array)
120W × 18 pieces/series × 19 arrays = 41080W = 342 pieces

 

 

The design of the demand capacity of battery：

*The coefficient of compensation: 1.45

*The amount of none sunshine day: one day

 

The demand capacity of battery ＝The power demand of emergency × The amount of none sunshine day × The coefficient of compensation.

The coefficient of compensation : Impedance in the battery, the voltage of the discharging stop, the voltage to reduce and compensate.

 

 

The design of the demand capacity of battery ＝83.2KwH/d × 1 day × 1.45 = 120.64KwH

 

 

↓

 

 

The design of the series-parallel：

*The voltage of the battery : 2V /piece

*The capacity of the battery : 200AH/piece

*The voltage of the inverter：

 

 

Input ; Specified voltage
300V； 288V
200V ；192V

 

 

The amount of the series＝ The specified voltage of the inverter ÷ The voltage of the battery

 

 

288V÷2V＝144pieces

 

 

The amount of the parallel ＝The demand capacity of battery ÷ The specified voltage of the inverter

 

 

120640wH÷288V÷200AH＝2.1列≒2列

 

 

Quantity of the battery ＝ 144pieces × 2arrays ＝ 288 pieces